(BASIC TEMP.28℃, INPUT TEMP.:60℃CEMENT + 10℃3/8” GRAVEL + 28℃3/4” GRAVEL + 26℃ SAND + 25℃ WATER)
|
(1)
SPECIFIC HEAT
Kcal/Kg℃ |
(2)
WEIGHT
Kg/M3 |
(3)
WATER CONTENT
Kg/M3 |
(4)
HEAT EQUIVALENT
Kcal/℃M3
(=1x2+3) |
(5)
INPUT TEMP.
℃ |
(6)
TEMP. DIFFERENCE WITH 28℃ |
(7)
HEAT DISCHARGE
Kcal/M3
(=4x6) |
CEMENT |
0.22 |
330 |
0 |
72.6 |
60 |
32 |
2,323 |
3/8” GRAVEL |
0.22 |
700 |
7 (1%) |
161 |
10 |
-18 |
-2,898 |
3/4” GRAVEL |
0.22 |
350 |
3.5 (1%) |
80.5 |
28 |
0 |
0 |
SAND |
0.22 |
780 |
62.4 (8%) |
234 |
26 |
-2 |
-468 |
WATER |
1 |
80 |
|
80 |
25 |
-3 |
-240 |
MIX HEAT |
|
|
|
|
|
|
2,586 |
TOTAL HEAT EQUIVALENT |
|
|
|
628.1 |
|
|
1,303 |
TOTAL HEAT DISCHARGE |
|
TEMP OF CONCRETE AFTER MIX=28℃+ΔT
ΔT=TOTAL HEAT DISCHARGE/TOTAL HEAT EQUIVALENT=1,303/628.1=2.07℃
TEMP AFTER MIX=28℃+ΔT=28+2.07=30.07℃ ≧28℃ (BASIC TEMP)
It shows when there is a shortage of ice water and only cooled 10℃3/8” gravel is available in the mixing process. The result fails to satisfy the basic requirement of the concrete batching plant.
We recommend you to add a new Cold Air Chiller to chill the 3/4” gravel and improve the situation.